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DGCA CPL AIR NAVIGATION · ASKED IN REAL EXAMS

Airspeed, Mach & Vertical Speed

70 questions on this topic, recalled by candidates after DGCA sittings between 2019 and 2026. Together they were asked 156 times; the most repeated come first. Pick a year to see only what was asked that year.

Asked in:
Q1Asked in 8 sittings:Mar 2024 · Regular 01Jun 2024 · RegularSep 2024 · Regular 03Mar 2025 · Regular 01Apr 2025 · OLODE 03May 2025 · OLODE 04Mar 2026 · Regular 01Aug 2026 · OLODE 06

At FL330 with temperature ISA + 15, the TAS is 487 kt. The Mach number is:

  1. A.0.78
  2. B.0.81
  3. C.0.84
  4. D.0.76
Show answer

B. 0.81

ISA at FL330 = -51 C, so -36 C = 237 K. LSS = 38.95 x sqrt(237) = 600 kt. M = 487 / 600 = 0.81.

The question was recalled without its options; these options were written to it.

Q2Asked in 8 sittings:Nov 2024 · OLODE 08Mar 2025 · Regular 01May 2025 · OLODE 04Jun 2025 · Regular 02Aug 2025 · OLODE 06Jan 2026 · OLODE 01May 2026 · OLODE 04Jul 2026 · OLODE 05

A conventional VSI works by comparing:

  1. A.pitot and static pressure
  2. B.static pressure in the capsule with static pressure in the case fed through a calibrated leak (metering unit)
  3. C.total pressure with a vacuum
  4. D.gyro precession
Show answer

B. static pressure in the capsule with static pressure in the case fed through a calibrated leak (metering unit)

The capsule receives static directly; the case receives it through a restriction, so in a climb or descent the case lags and the difference shows the rate. No pitot input - a blocked pitot does not affect it.

The question was recalled without its options; these options were written to it.

Q3Asked in 7 sittings:Sep 2023 · Regular 03Dec 2023 · RegularMar 2024 · Regular 01Jun 2024 · RegularDec 2024 · Regular 04Mar 2025 · Regular 01May 2026 · OLODE 04

What do the upper and lower limits of the yellow arc on an ASI represent?

  1. A.Upper limit VNE, lower limit VNO
  2. B.Upper limit VNO, lower limit VNE
  3. C.Upper limit VMO, lower limit VNE
Show answer

A. Upper limit VNE, lower limit VNO

The yellow (caution) arc starts at VNO, the top of the green arc, and ends at VNE, the red line. So the upper limit is VNE and the lower limit is VNO.

The question was recalled without its options; these options were written to it.

Q4Asked in 6 sittings:Sep 2022 · FC 03Aug 2023 · OLODENov 2023 · OLODE (30 Nov)Mar 2024 · Regular 01Jun 2024 · RegularFeb 2026 · OLODE 02

What is the local speed of sound at -25 C?

  1. A.674 kt
  2. B.644 kt
  3. C.614 kt
  4. D.661 kt
Show answer

C. 614 kt

LSS = 38.95 x sqrt(T in kelvin) = 38.95 x sqrt(248) = 614 kt. (661 kt is the sea-level ISA value at +15 C.)

The question was recalled without its options; these options were written to it.

Q5Asked in 6 sittings:Sep 2023 · Regular 03Nov 2023 · OLODE (29 Nov)Aug 2024 · OLODE 06Jun 2025 · Regular 02Jul 2025 · OLODE 05Mar 2026 · Regular 01

The static source of an ASI becomes blocked during a CLIMB. The ASI will:

  1. A.increase regardless of the actual speed
  2. B.progressively under-read
  3. C.progressively over-read
  4. D.stick at the speed at the moment of blockage
Show answer

B. progressively under-read

Trapped static stays at the higher (lower-altitude) pressure while real static falls; the capsule sees pitot - trapped static, which is too small: the ASI under-reads. In a DESCENT it over-reads.

The question was recalled without its options; these options were written to it.

Q6Asked in 6 sittings:May 2022Sep 2022 · FC 03Oct 2023 · OLODEMar 2024 · Regular 01Jul 2025 · OLODE 05Aug 2025 · OLODE 06

The temperature probe of a fast aircraft reads TAT. The static air temperature is:

  1. A.TAT + ram rise
  2. B.TAT - ram rise
  3. C.TAT x Mach
  4. D.the same as TAT
Show answer

B. TAT - ram rise

Air brought to rest on the probe heats up (ram rise): TAT = SAT + ram rise, so SAT = TAT - ram rise. ISA deviation uses SAT.

Q7Asked in 5 sittings:Aug 2023 · OLODENov 2023 · OLODE (30 Nov)Oct 2024 · OLODE 07Mar 2025 · Regular 01Feb 2026 · OLODE 02

On an ASI the colour markings from the low-speed end upwards are:

  1. A.white, green, yellow, then the red line
  2. B.red, white, yellow, green
  3. C.green, white, yellow, red
  4. D.white, yellow, green, red
Show answer

A. white, green, yellow, then the red line

White arc: flap operating range (VS0-VFE). Green: normal range (VS1-VNO). Yellow: caution range (VNO-VNE). Red line: VNE.

The question was recalled without its options; these options were written to it.

Q8Asked in 5 sittings:Jan 2019May 2022May 2024 · OLODE 04Apr 2025 · OLODE 03May 2026 · OLODE 04

Which statement about the Machmeter is correct?

  1. A.at constant CAS the Mach number decreases in a climb
  2. B.at constant CAS the Mach number increases in a descent
  3. C.the Machmeter reading is independent of temperature
  4. D.the Machmeter has a temperature probe
Show answer

C. the Machmeter reading is independent of temperature

The Machmeter works only from pitot and static pressure (Mach depends on (Pt - Ps)/Ps), so temperature never enters. At constant CAS the Mach number INCREASES in a climb and decreases in a descent - both other statements are reversed.

Q9Asked in 4 sittings:Oct 2021 · Attempt 2Oct 2023 · OLODENov 2023 · OLODE (30 Nov)Dec 2023 · Regular

CAS is IAS corrected for

  1. A.position error only
  2. B.instrument error only
  3. C.instrument error and position error
  4. D.density error
Show answer

C. instrument error and position error

CAS (also called RAS) is IAS corrected for both instrument error and position error.

The question was recalled without its options; these options were written to it.

Q10Asked in 4 sittings:Sep 2023 · Regular 03Jul 2024 · OLODE 05Aug 2024 · OLODE 06Aug 2026 · OLODE 06

The pitot tube and its drain become blocked; the static source is clear. During a DESCENT the ASI will:

  1. A.increase
  2. B.decrease
  3. C.stay constant
  4. D.read zero
Show answer

B. decrease

Pitot pressure is trapped; static increases as you descend, so pitot - static shrinks and the ASI falls, whatever the real speed. It now behaves like an altimeter: rising in a climb, falling in a descent.

The question was recalled without its options; these options were written to it.

Q11Asked in 4 sittings:Jul 2023 · OLODEAug 2023 · OLODENov 2023 · OLODE (30 Nov)Sep 2024 · Regular 03

A blocked pitot tube affects:

  1. A.the ASI (and Machmeter) only
  2. B.the ASI and the VSI
  3. C.the ASI, altimeter and VSI
  4. D.the altimeter only
Show answer

A. the ASI (and Machmeter) only

Only the ASI and Machmeter use pitot pressure. The altimeter and VSI use static alone, so a blocked STATIC source affects all of them.

The question was recalled without its options; these options were written to it.

Q12Asked in 4 sittings:Jun 2024 · RegularSep 2024 · Regular 03Mar 2025 · Regular 01Sep 2026 · Regular 03

A pitot tube facing into the airflow measures:

  1. A.static pressure only
  2. B.dynamic pressure only
  3. C.total pressure (static + dynamic)
  4. D.air density
Show answer

C. total pressure (static + dynamic)

The air brought to rest in the tube gives total (pitot) pressure = static + dynamic. The ASI subtracts static to leave the dynamic part.

The question was recalled without its options; these options were written to it.

Q13Asked in 3 sittings:Sep 2022 · FC 03Mar 2024 · Regular 01Mar 2026 · Regular 01

An aircraft descends at a constant Mach number in the standard atmosphere. The IAS will:

  1. A.increase, and the margin to low-speed buffet increases
  2. B.increase, and the margin to low-speed buffet decreases
  3. C.decrease
  4. D.stay constant
Show answer

A. increase, and the margin to low-speed buffet increases

Descending at constant Mach, the air gets denser and warmer: IAS (CAS) rises, moving the aircraft away from low-speed buffet and towards VMO - which is why the changeover from Mach to IAS is made in the descent.

The question was recalled without its options; these options were written to it.

Q14Asked in 3 sittings:Jan 2019Jun 2024 · RegularFeb 2026 · OLODE 02

What is the effect on the Mach number and TAS in an aircraft that is climbing with constant CAS?

  1. A.Mach number decreases; TAS decreases
  2. B.Mach number remains constant TAS increases
  3. C.Mach number increases; TAS increases
  4. D.Mach number increases; TAS remains constant
Show answer

C. Mach number increases; TAS increases

Climbing at constant CAS the Mach number and TAS both increase.

Q15Asked in 3 sittings:Apr 2024 · OLODE 03May 2024 · OLODE 04Jun 2024 · Regular

Flying at a constant CAS, as the density altitude increases the TAS:

  1. A.increases
  2. B.decreases
  3. C.stays the same
  4. D.increases only above the tropopause
Show answer

A. increases

TAS = CAS / sqrt(relative density). Higher density altitude means thinner air, so for the same CAS the TAS is higher.

Q16Asked in 3 sittings:May 2024 · OLODE 04Aug 2024 · OLODE 06Dec 2024 · Regular 04

Because the VSI measures the RATE of change of static pressure, position error:

  1. A.never affects it
  2. B.may cause errors during the take-off run
  3. C.affects it whenever the speed changes, even without a change of position error
  4. D.only affects it in a turn
Show answer

B. may cause errors during the take-off run

A VSI is fooled only while the position error is changing - e.g. as speed builds rapidly on the take-off run. It also lags for a few seconds when a climb or descent starts or stops (lag + manoeuvre error).

The question was recalled without its options; these options were written to it.

Q17Asked in 3 sittings:Dec 2023 · RegularOct 2024 · OLODE 07Aug 2026 · OLODE 06

An aircraft has a static vent on each side of the fuselage; the RIGHT one is blocked. In a sideslip to the RIGHT, the altimeter and ASI will:

  1. A.over-read
  2. B.under-read
  3. C.read correctly
  4. D.read zero
Show answer

A. over-read

In a right sideslip the right side meets the airflow (high pressure) and the left is in its lee (low pressure). With the right vent blocked, only the low left-side pressure is sensed: static too LOW - the altimeter over-reads and the ASI over-reads.

The question was recalled without its options; these options were written to it.

Q18Asked in 2 sittings:Mar 2024 · Regular 01Mar 2025 · Regular 01

If the static line to the ASI becomes blocked during a long descent, the danger is that the ASI:

  1. A.over-reads, showing the aircraft further from the stall than it really is
  2. B.under-reads, showing it closer to the stall than it is
  3. C.under-reads, leading to flap/gear operation above the limits
  4. D.over-reads, leading to flap/gear operation above the limits
Show answer

A. over-reads, showing the aircraft further from the stall than it really is

Static trapped at a lower (higher-altitude) pressure makes pitot - static too large as you descend: over-reading. The real speed is lower than shown - the stall is closer than you think.

The question was recalled without its options; these options were written to it.

Q19Asked in 2 sittings:Jun 2023 · RegularDec 2023 · Regular

In a standard atmosphere and at sea level, CAS is

  1. A.the same as TAS
  2. B.lower than TAS
  3. C.higher than TAS
Show answer

A. the same as TAS

CAS equals TAS only at ISA sea level, where density is 1.225 kg/m3.

Q20Asked in 2 sittings:Jun 2023 · RegularNov 2023 · OLODE (30 Nov)

During the climb after take-off from a contaminated runway, the pitot (total pressure) probe becomes blocked. The IAS will:

  1. A.decrease abruptly towards zero
  2. B.increase steadily
  3. C.increase abruptly towards VNE
  4. D.stay constant
Show answer

B. increase steadily

Trapped pitot pressure against a falling static pressure: the indicated speed climbs steadily with altitude, regardless of the real speed.

The question was recalled without its options; these options were written to it.

Q21Asked in 2 sittings:Jun 2023 · RegularMar 2024 · Regular 01

An aircraft flying at 7500 feet is cleared to descend to the level at 1000 feet. 6Nm before reaching a beacon is ground speed is 156 kts and rate of descent is 800 fpm. How many miles before the beacon should descent begin?

  1. A.30.2
  2. B.27.1
  3. C.11.1
Show answer

B. 27.1

Descent 7,500 to 1,000 ft = 6,500 ft at 800 ft/min = 8.1 min; at 156 kt that is 21.1 NM. Add the 6 NM still to run: start the descent 27.1 NM before the beacon.

As recalled, this question depended on a chart or table that is not reproduced here; the key is the recalled paper's answer.

Q22Asked in 2 sittings:Jun 2023 · RegularMar 2026 · Regular 01

If pitot line become block during climb ASI reading will

  1. A.Increase
  2. B.decrease
  3. C.Remain constant
Show answer

A. Increase

With the pitot blocked (and its drain closed) the trapped pressure stays constant while static pressure falls in the climb, so the ASI over-reads and increases.

Q23Asked in 2 sittings:Feb 2024 · OLODE 02Jun 2025 · Regular 02

In isothermal layer at constant Mach descent

  1. A.TAS increases
  2. B.TAS decreases
  3. C.TAS remains constant
Show answer

C. TAS remains constant

In an isothermal layer the speed of sound is constant, so at constant Mach the TAS is constant.

Q24Asked in 2 sittings:Nov 2023 · OLODE (30 Nov)Jun 2025 · Regular 02

The green arc of an ASI runs from:

  1. A.VS0 to VFE
  2. B.VS1 to VNO
  3. C.VNO to VNE
  4. D.VS1 to VNE
Show answer

B. VS1 to VNO

Green = normal operating range: lower end VS1 (stall, clean, max weight), upper end VNO (max structural cruising speed).

The question was recalled without its options; these options were written to it.

Q25Asked in 2 sittings:May 2022Mar 2024 · Regular 01

The errors to which the Machmeter is subject are:

  1. A.instrument, position, compressibility and manoeuvre-induced
  2. B.instrument, position and manoeuvre-induced
  3. C.instrument, position, barometric and manoeuvre-induced
  4. D.instrument, position, density and manoeuvre-induced
Show answer

B. instrument, position and manoeuvre-induced

The Machmeter uses a pressure RATIO, so it has no density or temperature error, and compressibility is built into its calibration. That leaves instrument, position and manoeuvre-induced errors.

The question was recalled without its options; these options were written to it.

Q26Asked in 2 sittings:Dec 2023 · RegularMar 2024 · Regular 01

When descending through an inversion at constant CAS?

  1. A.TAS decreases
  2. B.Mach number increases.
  3. C.Mach number remains constant.
Show answer

A. TAS decreases

Descending at constant CAS the air gets denser, so TAS falls (and the Mach number falls).

Q27Asked in 2 sittings:Aug 2024 · OLODE 06Mar 2026 · Regular 01

The correct order of corrections from indicated to true airspeed is:

  1. A.IAS - EAS - CAS - TAS
  2. B.IAS - CAS - EAS - TAS
  3. C.IAS - TAS - CAS - EAS
  4. D.CAS - IAS - EAS - TAS
Show answer

B. IAS - CAS - EAS - TAS

IAS + instrument and position error = CAS; CAS + compressibility = EAS; EAS + density error = TAS.

The question was recalled without its options; these options were written to it.

Q28Asked in 2 sittings:Sep 2022 · FC 03May 2026 · OLODE 04

Climbing at a constant Mach number below the tropopause in ISA conditions:

  1. A.CAS and TAS both decrease
  2. B.CAS increases, TAS decreases
  3. C.CAS decreases, TAS stays the same
  4. D.both increase
Show answer

A. CAS and TAS both decrease

Temperature falls in the climb, so the speed of sound falls: same Mach = lower TAS. Air also gets thinner, so CAS falls even faster.

Q29Asked in 2 sittings:Nov 2023 · OLODE (30 Nov)May 2025 · OLODE 04

Ice or debris disturbing the airflow around the static source causes:

  1. A.instrument error
  2. B.position (pressure) error
  3. C.density error
  4. D.compressibility error
Show answer

B. position (pressure) error

Position error is the error from the static vent sensing a pressure different from the true ambient pressure because of the local airflow - ice or debris round the vent changes exactly that.

The question was recalled without its options; these options were written to it.

Q30Asked in 2 sittings:Nov 2023 · OLODE (30 Nov)Aug 2026 · OLODE 06

In an isothermal layer, flying at a constant TAS, the Mach number:

  1. A.increases
  2. B.decreases
  3. C.stays constant
  4. D.depends on the CAS
Show answer

C. stays constant

Mach = TAS / speed of sound, and the speed of sound depends only on temperature. Constant temperature + constant TAS = constant Mach.

The question was recalled without its options; these options were written to it.

Q31Asked in 2 sittings:Sep 2023 · Regular 03Nov 2023 · OLODE (30 Nov)

A leak in the pitot (total pressure) line of a non-pressurised aircraft makes the ASI:

  1. A.over-read in a climb and under-read in a descent
  2. B.over-read
  3. C.under-read in a climb and over-read in a descent
  4. D.under-read
Show answer

D. under-read

In an unpressurised cabin the leak lets pitot pressure escape to roughly static pressure, so the difference sensed is too small: the ASI under-reads.

The question was recalled without its options; these options were written to it.

Q32Asked in 2 sittings:Sep 2024 · Regular 03Jun 2025 · Regular 02

An aircraft descends at a constant Mach number through an inversion (temperature falling as it descends). CAS and TAS:

  1. A.CAS increases, TAS decreases
  2. B.both increase
  3. C.both decrease
  4. D.CAS decreases, TAS increases
Show answer

A. CAS increases, TAS decreases

CAS rises in any descent at constant Mach (denser air). TAS = Mach x speed of sound, and the speed of sound falls with the colder air in the inversion, so TAS falls.

Q33Asked in 2 sittings:Apr 2024 · OLODE 03Sep 2024 · Regular 03

In an airspeed indicator, the capsule is fed with ...... and the case with ......:

  1. A.static; pitot (total) pressure
  2. B.pitot (total) pressure; static pressure
  3. C.static; vacuum
  4. D.vacuum; static
Show answer

B. pitot (total) pressure; static pressure

Total (pitot) pressure inside the capsule, static around it: the capsule expands with the difference, the dynamic pressure 1/2 rho V^2.

The question was recalled without its options; these options were written to it.

Q34Asked in 2 sittings:Nov 2023 · OLODE (30 Nov)Feb 2026 · OLODE 02

Ice blocks the pitot inlet but the drain hole remains open. The ASI will:

  1. A.over-read
  2. B.act like an altimeter
  3. C.gradually fall to zero
  4. D.freeze at the last reading
Show answer

C. gradually fall to zero

With the drain open, the pressure in the pitot line leaks away to atmospheric (static) pressure, so pitot - static becomes zero. If the drain is ALSO blocked, pressure is trapped and the ASI acts like an altimeter.

The question was recalled without its options; these options were written to it.

Q35Asked in 2 sittings:Aug 2023 · OLODEOct 2023 · OLODE

If the pitot (ram air) inlet and its drain are blocked but the static port stays open, the ASI will:

  1. A.read a little low
  2. B.read a little high
  3. C.react like an altimeter
  4. D.freeze at zero
Show answer

C. react like an altimeter

Trapped pitot pressure is compared with a changing static pressure: in a climb the static falls and the ASI rises; in a descent it falls - just like an altimeter.

The question was recalled without its options; these options were written to it.

Q36Asked in 2 sittings:May 2024 · OLODE 04Aug 2024 · OLODE 06

If the static vent becomes blocked during climb:

  1. A.the VSI will indicate an increasing rate of climb.
  2. B.the VSI will indicate a decreasing rate of climb,
  3. C.the VSI will return to zero..
Show answer

C. the VSI will return to zero..

Static pressure trapped at the blocked level while the aircraft climbs: the VSI returns to zero.

Q37Asked in 2 sittings:Mar 2022Jan 2026 · OLODE 01

At FL300 an aircraft flies at M 0.82 with OAT = ISA + 15 C. Its TAS is about:

  1. A.499 kt
  2. B.483 kt
  3. C.470 kt
  4. D.520 kt
Show answer

A. 499 kt

ISA at FL300 = -44.4 C, so OAT = -29.4 C = 243.8 K. Local speed of sound = 38.95 x sqrt(243.8) = 608 kt; TAS = 0.82 x 608 = 499 kt.

Q38Asked in 2 sittings:May 2022Mar 2023 · ATPL

Cylinder head and exhaust gas temperatures are normally measured by:

  1. A.a bourdon tube
  2. B.thermocouples
  3. C.a capsule
  4. D.a ratiometer bridge only
Show answer

B. thermocouples

A thermocouple (two dissimilar metals) generates a voltage proportional to the hot-junction temperature with no external power - used for CHT (on the hottest cylinder) and EGT.

Q39Asked in:Mar 2023 · ATPL

At FL330, temperature ISA + 15, the aircraft flies M 0.90. Its TAS is about:

  1. A.540 kt
  2. B.520 kt
  3. C.487 kt
  4. D.574 kt
Show answer

A. 540 kt

ISA at FL330 = -51 C; + 15 gives -36 C = 237 K. Speed of sound = 38.95 x sqrt(237) = 600 kt; TAS = 0.9 x 600 = 540 kt.

The question was recalled without its options; these options were written to it.

Q40Asked in:Apr 2025 · OLODE 03

A rate of descent of 500 ft/min is about:

  1. A.152 cm/s
  2. B.254 cm/s
  3. C.305 cm/s
  4. D.500 cm/s
Show answer

B. 254 cm/s

1 ft = 30.48 cm, so 500 ft/min = 15,240 cm/min = 15,240 / 60 = 254 cm/s.

Q41Asked in:Mar 2025 · Regular 01

The air data computer receives:

  1. A.pitot pressure, static pressure and total air temperature
  2. B.pressure and temperature only from the cabin
  3. C.GPS position
  4. D.heading
Show answer

A. pitot pressure, static pressure and total air temperature

From pitot, static and TAT (and often AoA) the ADC computes altitude, vertical speed, IAS/CAS, Mach, TAS and SAT.

The question was recalled without its options; these options were written to it.

Q42Asked in:Dec 2023 · Regular

Considering MMO and VMO, the captain of a pressurised aircraft begins his descent from a high flight level. In order to meet his scheduled time of arrival he decides to use maximum ground speed at any time of the descent. He will be limited by

  1. A.initially by MMO, then by VMO below a certain flight level
  2. B.initially by VMO, then by MMO below a certain flight level
  3. C.by the VMO in the still air
Show answer

A. initially by MMO, then by VMO below a certain flight level

At high level the Mach limit (MMO) is reached first; below the crossover altitude the airspeed limit VMO becomes the limit.

Q43Asked in:Dec 2023 · Regular

VMO is calculated based on

  1. A.TAS
  2. B.EAS
  3. C.CAS
Show answer

C. CAS

VMO is a calibrated airspeed limit.

Q44Asked in:Sep 2022 · FC 03

An aircraft at FL370 is required to commence descent when 100 NM from a DME facility and to cross the station at FL120. If the mean GS during the descent is 396 kt, the minimum rate of descent required is approximately

  1. A.1650 ft/min
  2. B.2400 ft/min
  3. C.1000 ft/min
Show answer

A. 1650 ft/min

Height to lose = 37,000 - 12,000 = 25,000 ft. Time = 100 / 396 h = 15.15 min. Rate = 25,000 / 15.15 = 1,650 ft/min.

Q45Asked in:Feb 2024 · OLODE 02

Static vents on BOTH sides of the fuselage (cross-coupled) are fitted mainly to:

  1. A.provide a backup if one is blocked
  2. B.reduce the error caused by sideslip or yaw
  3. C.increase sensitivity
  4. D.prevent icing
Show answer

B. reduce the error caused by sideslip or yaw

Averaging the two sides cancels the pressure difference created by sideslip/yaw. The alternate static source is the backup for blockage.

The question was recalled without its options; these options were written to it.

Q46Asked in:Jan 2019

An aircraft is descending down a 12% slope whilst maintaining a GS of 540 kt. The rate of descent of the aircraft is approximately:

  1. A.650 FT/MIN
  2. B.6500 FT/MIN
  3. C.4500 FT/MIN
  4. D.3900 FT/MIN
Show answer

B. 6500 FT/MIN

540 kt = 54,700 ft/min of ground distance; 12% of that = 6,560 ft/min, about 6,500 ft/min.

Q47Asked in:Jan 2019

When using the Vertical Speed Indicator, the pilot

  1. A.can rely on its readings in all attitudes of flight
  2. B.Can only rely on the readings when changing to horizontal flight
  3. C.Cannot rely on its readings, especially when a change of pitch Attitude is occurring
  4. D.can rely throughout the flight
Show answer

C. Cannot rely on its readings, especially when a change of pitch Attitude is occurring

The VSI lags and gives wrong readings during pitch changes.

Q48Asked in:Jan 2024 · Regular (Day 2)

An aircraft at FL350 is required to commence descent when 85 NM from a VOR to cross the VOR at FL80. The mean GS for the descent is 340 kt. What is the minimum rate of descent required?

  1. A.1800 ft/min
  2. B.1600 ft/min
  3. C.1700 ft/min
  4. D.1900 ft/min
Show answer

A. 1800 ft/min

Height to lose = 35,000 - 8,000 = 27,000 ft. Time = 85 / 340 h = 15 min. Rate = 27,000 / 15 = 1,800 ft/min.

Q49Asked in:Jan 2025 · OLODE 01

IAS 84 kt, OAT +10 C, pressure altitude 8,000 ft. The TAS is about:

  1. A.97 kt
  2. B.84 kt
  3. C.101 kt
  4. D.91 kt
Show answer

A. 97 kt

ISA at 8000 ft is -1 C, so ISA + 11. Air density ratio gives TAS = 84 x 1.15 = 97 kt (rule of thumb: +2 % per 1000 ft = 97 kt).

The question was recalled without its options; these options were written to it.

Q50Asked in:Jan 2026 · OLODE 01

If the static source AND the pitot are both blocked, the instruments affected are:

  1. A.ASI only
  2. B.altimeter and VSI only
  3. C.ASI, altimeter, VSI and Machmeter
  4. D.none, they all have their own sources
Show answer

C. ASI, altimeter, VSI and Machmeter

Static feeds the altimeter, VSI, ASI and Machmeter; pitot feeds the ASI and Machmeter. Block both and every pressure instrument is wrong.

The question was recalled without its options; these options were written to it.

Q51Asked in:Jun 2023 · Regular

The RIGHT static vent is blocked and the left is open. In a sideslip to the LEFT, the ASI and Machmeter will:

  1. A.under-read
  2. B.over-read
  3. C.show no change
  4. D.read zero
Show answer

A. under-read

Slipping left, the left side faces the airflow, so the open left vent senses a pressure ABOVE true static. Pitot - static is too small: the ASI (and Machmeter) under-read.

The question was recalled without its options; these options were written to it.

Q52Asked in:Jun 2023 · Regular

At a constant Mach decent Cas will

  1. A.Increase
  2. B.decrease
  3. C.remain constant
Show answer

A. Increase

In a constant-Mach descent the speed of sound rises, so CAS and IAS increase.

Q53Asked in:Jun 2025 · Regular 02

The airspeed indicator is calibrated to:

  1. A.conditions of the ISA
  2. B.conditions of the ISA at mean sea level
  3. C.an air density of 1013.25 g/m3
  4. D.indicate correctly in any atmosphere
Show answer

B. conditions of the ISA at mean sea level

The ASI is calibrated to read TAS only in ISA sea-level air (1.225 kg/m3, 1013.25 hPa, +15 C). Anywhere else density error makes IAS differ from TAS.

The question was recalled without its options; these options were written to it.

Q54Asked in:Jun 2025 · Regular 02

An aircraft at FL290, ISA deviation -6 C, has a CAS (RAS) of 255 kt. Its Mach number is about:

  1. A.0.67
  2. B.0.62
  3. C.0.72
  4. D.0.58
Show answer

A. 0.67

Mach depends only on the ratio of dynamic to static pressure, i.e. on CAS and pressure altitude - not on temperature. At FL290, 255 kt CAS gives M 0.67. The ISA deviation changes the TAS (here about 390 kt), not the Mach.

The question was recalled without its options; these options were written to it.

Q55Asked in:May 2022

EPR (engine pressure ratio) is:

  1. A.compressor inlet pressure / turbine outlet pressure
  2. B.turbine (jet pipe) outlet pressure / compressor inlet pressure
  3. C.fuel pressure / oil pressure
  4. D.cabin pressure / ambient pressure
Show answer

B. turbine (jet pipe) outlet pressure / compressor inlet pressure

EPR = exhaust (turbine outlet) total pressure divided by compressor inlet total pressure - a direct measure of thrust on many jets.

The question was recalled without its options; these options were written to it.

Q56Asked in:Mar 2024 · Regular 01

In a non-pressurized aircraft, if one or several static pressure ports are damaged, there is an ultimate emergency means for restoring a practically correct static pressure intake?

  1. A.Breaking the rate-of climb indicator glass window.
  2. B.Slightly opening a window to restore the ambient pressure in the cabin.
  3. C.Descending as much as possible in order to fly at a pressure as close to 1013.25 hPa as possible.
Show answer

A. Breaking the rate-of climb indicator glass window.

In an unpressurised aeroplane, breaking the VSI glass admits cabin (ambient) pressure to the static system as an emergency static source.

Q57Asked in:Mar 2024 · Regular 01

Descending from 15000 ft to 1000 ft, TAS 180 kts, HW -20 kts, ROD 500 FPM, Ground Distance?

  1. A.88 Nm
  2. B.75 Nm
  3. C.114 Nm
Show answer

B. 75 Nm

Time = 14,000 ft / 500 ft/min = 28 min. Ground speed with the 20 kt headwind = 160 kt: 160 x 28/60 = 75 NM.

Q58Asked in:May 2025 · OLODE 04

The static source of an unpressurised aircraft becomes blocked. The pilot's correct first action is to:

  1. A.select the alternate static source
  2. B.break the VSI glass
  3. C.descend immediately
  4. D.switch off pitot heat
Show answer

A. select the alternate static source

Select the alternate static source (usually inside the cabin; it may make the instruments over-read slightly). Breaking the VSI glass is the last-resort way to vent the system to cabin pressure if there is no alternate.

Q59Asked in:May 2026 · OLODE 04

The ISA temperature at FL330 is about:

  1. A.-51 C
  2. B.-56.5 C
  3. C.-36 C
  4. D.-66 C
Show answer

A. -51 C

ISA: +15 C at sea level, falling about 2 C per 1000 ft: 15 - 66 = -51 C (-50.3 with 1.98). -56.5 C is the tropopause value, reached at 36,090 ft.

The question was recalled without its options; these options were written to it.

Q60Asked in:May 2026 · OLODE 04

Pressure altitude 30,000 ft, TAT -10 C, Mach 0.82. The density altitude is about:

  1. A.30,400 ft
  2. B.29,600 ft
  3. C.31,200 ft
  4. D.30,000 ft
Show answer

A. 30,400 ft

First remove the ram rise: SAT = TAT / (1 + 0.2 M^2) = 263 / 1.134 = 232 K = -41 C. ISA at 30,000 ft is -44.4 C, so ISA + 3. Density altitude = 30,000 + 3 x 120 = about 30,400 ft.

The question was recalled without its options; these options were written to it.

Q61Asked in:Aug 2026 · OLODE 06

Descending from high altitude at a constant Mach number, the speed limit reached first and then the next is:

  1. A.VMO first, then MMO
  2. B.MMO first, then VMO
  3. C.only VMO
  4. D.only MMO
Show answer

B. MMO first, then VMO

Up high the Mach limit (MMO) governs; descending at constant Mach the IAS rises until VMO is reached, after which the crew flies IAS.

The question was recalled without its options; these options were written to it.

Q62Asked in:Aug 2023 · OLODE

An aircraft at 120 kt TAS needs a rate 1 turn. The bank angle required is about:

  1. A.36 deg
  2. B.19 deg
  3. C.12 deg
  4. D.30 deg
Show answer

B. 19 deg

tan(bank) = V x rate / g = 61.7 m/s x 0.0524 rad/s / 9.81 = 0.33, bank = 18 deg. Rule of thumb: TAS/10 + 7 = 19 deg.

The question was recalled without its options; these options were written to it.

Q63Asked in:Aug 2023 · OLODE

The local speed of sound is equal to (K = a constant):

  1. A.K x sqrt(temperature F) knots
  2. B.K x sqrt(temperature in kelvin) knots
  3. C.K x sqrt(temperature C) knots
  4. D.K x sqrt(temperature in kelvin) metres per second
Show answer

B. K x sqrt(temperature in kelvin) knots

The correct answer is: K x sqrt(temperature in kelvin) knots.

The question was recalled without its options; these options were written to it.

Q64Asked in:Dec 2023 · Regular

The white arc of an ASI runs from:

  1. A.VS0 to VFE
  2. B.VS1 to VNO
  3. C.VS0 to VNO
  4. D.VFE to VNE
Show answer

A. VS0 to VFE

White = flap operating range: VS0 (stall with full flap) to VFE (maximum flap-extended speed).

The question was recalled without its options; these options were written to it.

Q65Asked in:May 2024 · OLODE 04

When descending through an isothermal layer at constant CAS:

  1. A.Mach number increases.
  2. B.Mach number decreases.
  3. C.Mach number remains constant
Show answer

B. Mach number decreases.

In an isothermal layer the speed of sound is constant; at constant CAS the TAS and hence the Mach number fall in the descent.

Q66Asked in:May 2024 · OLODE 04

IAS 120 kt, FL 80, OAT +20 deg C. What is the TAS?

  1. A.141 kt
  2. B.135 kt
  3. C.144 kt
Show answer

A. 141 kt

At FL80 with +20 C (ISA +21): density ratio = 0.743 / 1.017 = 0.730, so TAS = 120 / sqrt 0.730 = 140-141 kt.

The question was recalled without its options; these options were written to it.

Q67Asked in:Mar 2025 · Regular 01

An instantaneous VSI (IVSI) removes the lag of a normal VSI by using:

  1. A.a pitot input
  2. B.an accelerometer (dashpot) that reacts at once to vertical acceleration
  3. C.a gyro
  4. D.a larger metering unit
Show answer

B. an accelerometer (dashpot) that reacts at once to vertical acceleration

A small spring-loaded piston (dashpot) moves with vertical acceleration and produces an immediate pressure difference, so the needle responds at once while the normal metering takes over.

Q68Asked in:Aug 2026 · OLODE 06

Using ram rise = (TAS/100)^2 deg C, at a TAS of 400 kt the TAT exceeds the SAT by about:

  1. A.16 C
  2. B.4 C
  3. C.40 C
  4. D.8 C
Show answer

A. 16 C

Ram rise = (TAS/100)^2 = (400/100)^2 = 16 C, so TAT is about 16 C warmer than SAT.

Q69Asked in:Feb 2026 · OLODE 02

At a constant IAS and pressure altitude, if the OAT increases the TAS:

  1. A.increases
  2. B.decreases
  3. C.stays the same
  4. D.depends on the Mach number
Show answer

A. increases

Warmer air is less dense; the same IAS needs a higher TAS (roughly +1 % per 5 C).

Q70Asked in:Jun 2024 · Regular

Total air temperature (TAT) is:

  1. A.static air temperature plus the ram rise
  2. B.static air temperature minus the ram rise
  3. C.the same as static air temperature at all speeds
  4. D.the temperature at the tropopause
Show answer

A. static air temperature plus the ram rise

Air brought to rest on the probe is heated by compression: TAT = SAT + ram rise. The ram rise grows with the square of TAS (about 1 deg C at 100 kt, about 9 deg C at 300 kt in round figures).

These are candidates' recollections, not official DGCA papers: wording can differ from the paper as set. Every answer was checked against the DGCA CARs, AIP India, ICAO documents or worked calculation (independent check completed 17 Oct 2026). Spotted a mistake? Tell us and we will check it against the source.