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RTR(A) — CH.10

ModulationRadio Telephony — DGCA CPL practice questions

Question 1 of 16

In amplitude modulation, what is varied?

A.The amplitude of the carrier
B.The frequency of the carrier
C.The speed of light
D.The antenna length

All 16 questions — Modulation

Radio Telephony · DGCA CPL. The correct option is marked on each.

  1. Q1. In amplitude modulation, what is varied?

    • A.The amplitude of the carrier
    • B.The frequency of the carrier
    • C.The speed of light
    • D.The antenna length

    Why: AM varies the carrier's amplitude in step with the audio; frequency stays fixed.

  2. Q2. One reason a voice cannot be transmitted directly is that it would require:

    • A.Too little power
    • B.An impractically long antenna (its wavelength is enormous)
    • C.A satellite
    • D.Frequency modulation

    Why: n impractically long antenna (its wavelength is enormous). Audio wavelengths are hundreds of km; modulating a high-frequency carrier allows a short antenna and frequency sharing.

  3. Q3. The information in an AM signal is carried in the:

    • A.Carrier
    • B.Sidebands
    • C.Antenna
    • D.Local oscillator

    Why: The carrier carries no information; the sidebands do.

  4. Q4. If the highest audio frequency is 3 kHz, the AM bandwidth is:

    • A.3 kHz
    • B.6 kHz
    • C.1.5 kHz
    • D.9 kHz

    Why: AM bandwidth = 2 × highest audio frequency = 2 × 3 = 6 kHz.

  5. Q5. Modulating beyond 100% depth causes:

    • A.A clearer signal
    • B.More range
    • C.Distortion and interference to adjacent channels
    • D.Lower frequency

    Why: istortion and interference to adjacent channels. Over-modulation distorts the audio and splatters into neighbouring channels.

  6. Q6. At 100% AM modulation, the proportion of power in the carrier is about:

    • A.33%
    • B.67%
    • C.100%
    • D.0%

    Why: About two-thirds of the power is in the carrier, which carries no information.

  7. Q7. In FM, what is held constant?

    • A.Frequency
    • B.Amplitude
    • C.Wavelength of the audio
    • D.Bandwidth

    Why: mplitude. FM varies frequency while amplitude stays constant — hence its noise immunity.

  8. Q8. FM is generally NOT used for VHF aviation voice because of its:

    • A.Low cost
    • B.Capture effect (weaker signal silenced)
    • C.Wide range
    • D.Use of sidebands

    Why: apture effect (weaker signal silenced). FM's capture effect would silently suppress a second transmitting aircraft — unsafe.

  9. Q9. Aviation VHF voice uses AM mainly because:

    • A.It is cheaper
    • B.Two simultaneous transmissions produce an audible heterodyne, alerting users
    • C.It has the longest range
    • D.It needs no antenna

    Why: AM reveals when two stations transmit together (a squeal); FM's capture effect would silently lose one.

  10. Q10. SSB is preferred for HF because it is:

    • A.Simpler to receive
    • B.More power- and bandwidth-efficient
    • C.Immune to all fading
    • D.Higher frequency

    Why: SSB suppresses the carrier and one sideband, concentrating power and halving bandwidth.

  11. Q11. SSB uses how much bandwidth compared with full AM?

    • A.Twice
    • B.Half
    • C.The same
    • D.Four times

    Why: Transmitting one sideband instead of two halves the bandwidth.

  12. Q12. The emission designator for aviation VHF voice (AM telephony) is:

    • A.J3E
    • B.A3E
    • C.F3E
    • D.A1A

    Why: 3E. A3E = AM double-sideband telephony (VHF voice); J3E = SSB telephony (HF voice).

  13. Q13. The aviation receiver architecture that converts every signal to a fixed intermediate frequency is the:

    • A.Direct-conversion receiver
    • B.Superheterodyne receiver
    • C.Crystal set
    • D.Regenerative receiver

    Why: The superheterodyne mixes the signal down to a fixed IF for easy selectivity and gain.

  14. Q14. In the transmitter chain, the stage that generates the carrier is the:

    • A.Modulator
    • B.Oscillator
    • C.Power amplifier
    • D.Antenna

    Why: The oscillator generates the carrier; the modulator then mixes the audio onto it.

  15. Q15. Modulation depth m is defined as:

    • A.Carrier voltage ÷ audio voltage
    • B.Audio (modulating) voltage ÷ carrier voltage
    • C.Frequency ÷ wavelength
    • D.Power ÷ bandwidth

    Why: udio (modulating) voltage ÷ carrier voltage. m = Vm/Vc, usually expressed as a percentage.

  16. Q16. Compared with AM, FM generally requires:

    • A.Less bandwidth
    • B.More bandwidth
    • C.No bandwidth
    • D.The same bandwidth

    Why: By Carson's rule, FM bandwidth ≈ 2(deviation + fmax), usually more than AM.