DGCA CPL / ATPL • General Navigation

Chapter 2
Great Circles, Rhumb Lines
& Directions on the Earth

DGCA CPL/ATPL Study Notes • Interactive Colour Edition
GC vs Rhumb Line • DIID Rule • Distance Calculations • Six Worked Examples
Compiled by Capt. Pankaj Pahil
www.ghostaviator.com

Contents

  1. 1. A Reminder about Great Circles
  2. 2. The Rhumb Line — Definition & Properties
  3. 3. Lines That Are Both Great Circles and Rhumb Lines
  4. 4. Great Circle Direction — The DIID Rule
  5. 5. Distance on the Earth — Units & Conversions
  6. 6. Variations in the Length of a Nautical Mile
  7. 7. Conversion Factors
  8. 8. Great Circle Distances — Six Worked Examples
  9. 9. Mean Latitude
  10. Practice Questions & Detailed Answers
  11. Master Reference Tables

1. A Reminder about Great Circles

🔎 Definition

A Great Circle is a circle on the surface of the Earth whose centre and radius are those of the Earth itself. It is called "great" because a disc cut in the plane of the Great Circle would have the largest area achievable — it divides the Earth into two equal hemispheres.

Figure 1 — A Great Circle — its centre and radius are those of the Earth itself
Figure 1 — A Great Circle — its centre and radius are those of the Earth itself

Key properties:

2. The Rhumb Line — Definition & Properties

🔎 Definition

A Rhumb Line is a regularly curved line on the surface of the Earth that cuts all meridians at the same angle — a line of constant direction.

Figure 2 — Moscow to Vancouver — Rhumb Line track plotted on a Mercator chart
Figure 2 — Moscow to Vancouver — Rhumb Line track plotted on a Mercator chart

The constant-direction property was enormously important to mariners and early aviators, who navigated by compass heading along straight Mercator chart tracks. Unlike the Great Circle, the Rhumb Line is not the shortest distance (except along the Equator, a meridian, or a parallel of latitude).

Figure 3 — Moscow to Vancouver — Great Circle track; note how it swings close to the North Pole
Figure 3 — Moscow to Vancouver — Great Circle track; note how it swings close to the North Pole
Figure 4 — Moscow to Vancouver — Great Circle track (curved, shorter) compared with Rhumb Line (straight, longer)
Figure 4 — Moscow to Vancouver — Great Circle track (curved, shorter) compared with Rhumb Line (straight, longer)

The Great Circle is always the shorter path; the Rhumb Line is always the longer one (again, except for the special cases — Equator, meridians).

Figure 5 — Great Circle track from Moscow to Vancouver plotted on a Mercator chart — track direction changes from ~330° to ~270° to ~210°
Figure 5 — Great Circle track from Moscow to Vancouver plotted on a Mercator chart — track direction changes from ~330° to ~270° to ~210°

GC vs Rhumb Line — Relative Position

⚠ Critical Exam Rule

There is only one Rhumb Line between any two points.

3. Lines That Are Both Great Circles and Rhumb Lines

✈ The Only Two Types

The only lines that are simultaneously Great Circles AND Rhumb Lines are:

Note: Parallels of latitude (other than the Equator) are Rhumb Lines but are Small Circles — their plane does not pass through the Earth's centre.

4. Great Circle Direction — The DIID Rule

Because a Great Circle track curves toward the nearer Pole, its direction changes continuously. The pattern of this change is captured in the DIID rule.

Figure 6 — Great Circle track direction change for an East–West Rhumb Line in the Northern and Southern hemispheres
Figure 6 — Great Circle track direction change for an East–West Rhumb Line in the Northern and Southern hemispheres

Understanding DIID

Consider an East–West Rhumb Line track (090° or 270°) at ~50°N or ~50°S:

HemisphereGoing East (→)Going West (←)
Northern GC track starts high (030°), swings to 090°, finishes low (150°) — track angle INCREASING GC track starts low (330°), swings to 270°, finishes high (210°) — track angle DECREASING
Southern GC track starts low (150°), swings to 090°, finishes high (030°) — track angle DECREASING GC track starts high (210°), swings to 270°, finishes low (330°) — track angle INCREASING
Figure 7 — The DIID diagram — Decreasing, Increasing, Increasing, Decreasing — GC track direction change relative to the Rhumb Line
Figure 7 — The DIID diagram — Decreasing, Increasing, Increasing, Decreasing — GC track direction change relative to the Rhumb Line

📚 Reading the DIID Diagram

Reading the four quadrants clockwise from the top-left: D–I–I–D (Decreasing–Increasing–Increasing–Decreasing).

In ALL cases: the GC direction always changes towards the Equator.

5. Distance on the Earth — Units & Conversions

Metric Units

UnitEquivalent
1 metre (m)100 cm = 1 000 mm
1 kilometre (km)1/10 000th of Equator-to-Pole distance → Earth circumference = 40 000 km
1 km3 280 ft
1 m3.28 ft

Imperial Units

UnitEquivalent
1 foot (ft)12 inches
1 yard (yd)3 feet
1 inch2.54 cm
1 statute mile5 280 ft

The Nautical Mile

✈ The Most Important Aviation Distance Unit

The nautical mile is directly related to the Earth's angular measurements:

Angular MeasurementDistance
1° of latitude60 NM
Equator to either Pole (90°)5 400 NM
Earth circumference (360°)21 600 NM

6. Variations in the Length of a Nautical Mile

Figure 8 — Geodetic and geocentric latitude — how the radius of curvature varies with latitude, causing the NM length to vary
Figure 8 — Geodetic and geocentric latitude — how the radius of curvature varies with latitude, causing the NM length to vary

The full definition: the NM is the arc of a Great Circle that subtends 1 minute of arc at the centre of curvature. Because the Earth is an oblate spheroid, the radius of curvature varies with latitude:

LocationRadius of curvatureNM length
EquatorSmallest (most curved)~6 048 ft (shortest)
Standard (mean)Mean6 076.1 ft (International NM = 1 852 m)
PolesLargest (flattest)~6 108 ft (longest)

📚 Exam Use

For all DGCA exam calculations, use the Standard NM of 6 080 ft. The variation between 6 048 ft and 6 108 ft is not examined computationally — it is a conceptual understanding question only.

7. Conversion Factors

ConversionValue
5 400 NM =10 000 km
21 600 NM =40 000 km
1 NM =1 852 m = 6 080 ft
1 km =3 280 ft
1 km =0.5400 NM (= 5400/10000)
1 NM =1.852 km

📚 Ratio Method for NM ↔ km

Use the circumference ratio: 21 600 NM = 40 000 km.
Therefore: NM × (40 000/21 600) = km  |  km × (21 600/40 000) = NM
Or simply: NM × 1.852 = km  |  km ÷ 1.852 = NM

8. Great Circle Distances — Six Worked Examples

🔎 Scope of DGCA Exam Questions

General GC distance calculation requires spherical geometry — not in the DGCA syllabus. Exam questions are limited to points on special Great Circles: the same meridian, meridian & anti-meridian, or the Equator. There are five general cases plus a special antipodal case — all six are shown below.

How to Identify Which Case Applies

ConditionCase
Same longitude, same hemisphereCase 1 — Ch.lat direct
Same longitude, different hemispheresCase 2 — Ch.lat = sum of lats
Longitudes add to 180°, same hemisphereCase 3 — Route via nearer Pole
Longitudes add to 180°, different hemispheresCase 4 — Route via nearer Pole
Both at 0° latitude (Equator)Case 5 — Ch.long at Equator
Same lat N & S, lons add to 180°Case 6 — Antipodal (10 800 NM)

Case 1 — Same Meridian, Same Hemisphere

Figure 9 — Case 1 — Same meridian, same hemisphere: London (51°37'N) to Accra (06°48'N) along 000°12'W
Figure 9 — Case 1 — Same meridian, same hemisphere: London (51°37'N) to Accra (06°48'N) along 000°12'W

Example: London (51°37'N 000°12'W) to Accra (06°48'N 000°12'W)

Step 1 — Confirm same meridian: both at 000°12'W ✓
Step 2 — Ch.lat: 51°37' − 06°48' = 44°49'S (travelling south)
Step 3 — Convert to NM: (44 × 60) + 49 = 2 689 NM
Direction of flight: South (180°T)

Case 2 — Same Meridian, Different Hemispheres

Figure 10 — Case 2 — Same meridian, different hemispheres: Durban (29°30'S) to Leningrad (59°47'N) along 030°30'E
Figure 10 — Case 2 — Same meridian, different hemispheres: Durban (29°30'S) to Leningrad (59°47'N) along 030°30'E

Example: Durban (29°30'S 030°30'E) to Leningrad (59°47'N 030°30'E)

Step 1 — Confirm same meridian: both at 030°30'E ✓
Step 2 — Ch.lat: 29°30' + 59°47' = 89°17'N (crossing the Equator, travelling north)
Step 3 — Convert to NM: (89 × 60) + 17 = 5 357 NM
Direction of flight: North (360°T)

Case 3 — Meridian and Anti-Meridian, Same Hemisphere

Figure 11 — Case 3 — Meridian and anti-meridian, same hemisphere: Rome (41°55'N 011°10'E) to Honolulu (21°17'N 168°50'W) — route goes over the North Pole
Figure 11 — Case 3 — Meridian and anti-meridian, same hemisphere: Rome (41°55'N 011°10'E) to Honolulu (21°17'N 168°50'W) — route goes over the North Pole

Example: Rome (41°55'N 011°10'E) to Honolulu (21°17'N 168°50'W)

Step 1 — Confirm meridian/anti-meridian: 011°10'E + 168°50'W = 180° ✓
Step 2 — Route: GC goes over the North Pole (both in Northern Hemisphere)
Step 3 — Angular distance: 180° − (41°55' + 21°17') = 180° − 63°12' = 116°48'
Alternative: (90° − 41°55') + (90° − 21°17') = 48°05' + 68°43' = 116°48' ✓
Step 4 — NM: (116 × 60) + 48 = 7 008 NM
Direction of flight: Initially North (360°T), then South (180°T) after the pole

Case 4 — Meridian and Anti-Meridian, Different Hemispheres

Figure 12 — Case 4 — Meridian and anti-meridian, different hemispheres: Tokyo (35°57'N 135°35'E) to Rio de Janeiro (22°10'S 044°25'W) — route via the North Pole
Figure 12 — Case 4 — Meridian and anti-meridian, different hemispheres: Tokyo (35°57'N 135°35'E) to Rio de Janeiro (22°10'S 044°25'W) — route via the North Pole

Example: Tokyo (35°57'N 135°35'E) to Rio de Janeiro (22°10'S 044°25'W)

Step 1 — Confirm meridian/anti-meridian: 135°35'E + 044°25'W = 180° ✓
Step 2 — Route: Draw diagram — route via North Pole is shorter
Step 3 — Angular distance (via N Pole):
   Tokyo → N Pole: 90° − 35°57' = 54°03'
   N Pole → Equator: 90°
   Equator → Rio: 22°10'
   Total: 54°03' + 90° + 22°10' = 166°13'
Step 4 — NM: (166 × 60) + 13 = 9 973 NM
Check (via S Pole would give 193°47'): 360° − 193°47' = 166°13' ✓ — or: 21 600 − 11 627 = 9 973 NM ✓

✎ Self-Check: Wrong-direction check for Case 4

If your angular distance exceeds 180°, you've gone the wrong way around. Subtract from 360° for the angular answer, or subtract from 21 600 NM for the distance.

Case 5 — Two Points on the Equator

Figure 13 — Case 5 — Two points on the Equator: Dakar (000°N 016°35'W) to Singapore (000°N 103°55'E) — diagram viewed from above North Pole
Figure 13 — Case 5 — Two points on the Equator: Dakar (000°N 016°35'W) to Singapore (000°N 103°55'E) — diagram viewed from above North Pole

Example: Dakar (00°00'N 016°35'W) to Singapore (00°00'N 103°55'E)

Step 1 — Both on Equator: ✓ (Equator is a Great Circle)
Step 2 — Ch.long: 016°35'W + 103°55'E = 120°30'E (going east from Dakar)
Step 3 — NM (Equator only — longitude minutes = NM): (120 × 60) + 30 = 7 230 NM
Direction of flight: East (090°T)

⚠ Only at the Equator!

The conversion 1 minute of longitude = 1 NM is valid ONLY AT THE EQUATOR. At any other latitude, you must use the departure formula (covered in the Departure chapter).

Case 6 — Antipodal Points (Special Case)

Figure 14 — Case 6 — Antipodal points: Greenwich (51°30'N 000°00'E) and Antipodes Island (51°30'S 180°00'E/W) — diametrically opposite on the Earth
Figure 14 — Case 6 — Antipodal points: Greenwich (51°30'N 000°00'E) and Antipodes Island (51°30'S 180°00'E/W) — diametrically opposite on the Earth

Example: Greenwich (51°30'N 000°00'E) to Antipodes Island (51°30'S 180°00'E)

Step 1 — Antipodal check: Equal latitudes N & S, longitudes add to 180° ✓
Step 2 — GC distance between any point and its antipode: always 180° = 10 800 NM
Note: Because the points are diametrically opposite, infinitely many Great Circles connect them.

9. Mean Latitude

The mean latitude between two positions is their arithmetic average. It is used in departure calculations (Ch.15).

Method

✎ Worked Examples

Example 1 — same hemisphere: Mean lat of 52°17'N and 17°57'N
52°17' + 17°57' = 70°14' ÷ 2 = 35°07'N

Example 2 — different hemispheres: Mean lat of 35°25'N and 13°38'S
Total span = 35°25' + 13°38' = 49°03'. Half = 24°31.5'.
Mean lat = 35°25'N − 24°31.5' = 10°53.5'N

📚 Quick Revision Summary — Chapter 2

Practice Questions & Detailed Answers

11 questions (many with sub-parts) • Calculation, conceptual & MCQ • Full worked solutions

Q1. What is the change of latitude between the following positions?
(a) 52°15'N to 39°35'N   (b) 49°35'N to 60°20'S   (c) 74°20'S to 34°30'S   (d) 71°20'N to 86°45'N over the North Pole
Anchor: §8 — Change of Latitude
▶ Show answer & explanation
PartCalculationAnswer
(a)52°15' − 39°35' = 12°40' South12°40'S
(b)49°35'N + 60°20'S (cross Equator) = 109°55' South109°55'S
(c)74°20'S → 34°30'S: 74°20' − 34°30' = 39°50' North39°50'N
(d)71°20'N→Pole: 18°40' + Pole→86°45'N: 3°15' = 21°55'21°55'

Part (b) note: When crossing the Equator, add both latitudes (49°35' + 60°20' = 109°55').

Part (c) note: Both in Southern hemisphere — the aircraft travels northward (toward less southerly latitude). Subtract the smaller from the larger: 74°20' − 34°30' = 39°50'N.

Part (d) note: "Over the North Pole" means the route passes through 90°N and continues on the opposite meridian. From 71°20'N to the pole = 18°40'; pole to 86°45'N = 3°15'. Total = 21°55'.

Instructor's Note: Source key verified. All four answers confirmed. No discrepancy.
Q2. What is the distance in nautical miles and kilometres from position A (41°25'N) to position B (79°30'N)? Both are on the same meridian.
Anchor: §8 — Case 1
▶ Show answer & explanation
Distance: 2 285 NM  |  4 232 km

Step 1 — Ch.lat: 79°30' − 41°25' = 38°05'N

Step 2 — NM: (38 × 60) + 5 = 2 285 NM

Step 3 — km: 2 285 × 1.852 = 4 232 km (or 4 230 km using the nav computer)

Instructor's Note: Source key: 2 285 NM / 4 232 km. Verified. No discrepancy.
Q3. What is the change of longitude between the following positions?
(a) 075°40'W to 125°35'W   (b) 001°20'E to 004°20'W   (c) 150°40'E to 179°30'E   (d) 162°36'W to 140°42'E
Anchor: §8 — Change of Longitude
▶ Show answer & explanation
PartCalculationAnswer
(a)125°35' − 075°40' = 49°55' West (same side)49°55'W
(b)001°20' + 004°20' = 05°40' West (opposite sides)05°40'W
(c)179°30' − 150°40' = 28°50' East (same side)28°50'E
(d)162°36' + 140°42' = 303°18' → shorter arc: 360° − 303°18' = 56°42'W56°42'W

Rule: same side → subtract; opposite sides → add. If the result exceeds 180°, take the supplement (360° − result) — this is the shorter arc.

Part (d) detailed: 162°36'W and 140°42'E are on opposite sides, so add: 162°36' + 140°42' = 303°18'. Since 303°18' > 180°, the shorter arc is 360° − 303°18' = 56°42'. Going westward from 162°36'W by 56°42' takes you through the anti-meridian to 140°42'E.

Instructor's Note: Source key notes "(d): Not 303°18' — we want the smaller arc." Confirmed. No discrepancy.
Q4. Give the direction and the change of latitude and longitude from X to Y in each case:
(a) 50°31'N 006°30'W → 52°00'N 008°35'W
(b) 47°32'N 002°46'W → 43°56'N 001°33'W
(c) 61°47'N 003°46'W → 62°13'N 001°36'E
(d) 31°27'S 091°47'E → 35°57'N 096°31'E
(e) 51°05'N 177°42'E → 51°06'N 167°42'W
Anchor: §8 — Ch.lat & Ch.long
▶ Show answer & explanation
PartCh.latCh.long
(a)01°29'N002°05'W
(b)03°36'S001°13'E
(c)00°26'N005°22'E
(d)67°24'N004°44'E
(e)00°01'N014°36'E

(a) Lat: 52°00' − 50°31' = 01°29'N. Long: 008°35'W − 006°30'W = 002°05'W (going further west).

(b) Lat: 43°56' − 47°32' = 03°36'S (going south). Long: 002°46'W → 001°33'W = 001°13'E (going east, less westerly).

(c) Lat: 62°13' − 61°47' = 00°26'N. Long: 003°46'W + 001°36'E = 005°22'E (crossing prime meridian).

(d) Lat: 35°57'N + 31°27'S = 67°24'N (cross Equator northbound). Long: 096°31' − 091°47' = 004°44'E.

(e) Lat: 51°06' − 51°05' = 00°01'N. Long: 177°42'E → 167°42'W — going east: 177°42'E to 180° = 2°18', then 180° to 167°42'W = 12°18'. Total = 014°36'E (shorter arc eastward).

Instructor's Note: All five sub-answers verified against source key. No discrepancies.
Q5. Give the shortest distance in nautical miles and kilometres between the following positions:
(a) 52°06'N 002°32'E and 53°36'N 002°32'E   (b) 04°41'S 163°36'W and 03°21'N 163°36'W
(c) 62°00'N 093°00'E and 62°00'N 087°00'W   (d) 00°00'N 176°00'E and 00°00'N 173°00'W
(e) 43°57'N 071°37'W and 43°57'S 108°23'E
Anchor: §8 — All six cases
▶ Show answer & explanation
PartCaseNMkm
(a)Case 1 (same meridian, same hemi)90 NM167 km
(b)Case 2 (same meridian, diff hemi)482 NM893 km
(c)Case 3 (merid+anti-merid, same hemi)3 360 NM6 223 km
(d)Case 5 (Equator)660 NM1 222 km
(e)Case 6 (Antipodal)10 800 NM20 000 km

(a) Same lon 002°32'E. Ch.lat = 53°36' − 52°06' = 01°30' = 90 NM. × 1.852 = 167 km.

(b) Same lon 163°36'W. Ch.lat = 04°41' + 03°21' = 08°02' = 482 NM. × 1.852 = 893 km.

(c) 093°00'E + 087°00'W = 180° → Case 3. Both 62°N → route over N Pole. Angular = 180° − (62° + 62°) = 56° = 3 360 NM. × 1.852 = 6 223 km.

(d) Both on Equator → Case 5. Ch.long: 176°E + 173°W = 349°; shorter arc = 360° − 349° = 11°. At Equator: 11° × 60 = 660 NM. × 1.852 = 1 222 km.

(e) 071°37'W + 108°23'E = 180° AND equal lats N/S → Antipodal (Case 6). Distance = 180° = 10 800 NM = 20 000 km.

Instructor's Note: All five answers confirmed against source key. No discrepancies.
Q6. An aircraft is to fly from 72°00'N 002°30'E to 72°00'N 177°30'W on the shortest possible route.
(a) Give the initial True track direction.   (b) Will the track direction remain the same?   (c) Why/why not?
Anchor: §8 — Case 3
▶ Show answer & explanation

(a) Initial track: 360°(T) — True North
(b) Track changes: No
(c) Route is over the North Pole. Initial track is True North; once past the pole, the track becomes True South (180°T).

Step 1 — Identify case: 002°30'E + 177°30'W = 180° → meridian/anti-meridian. Both at 72°N → same hemisphere → Case 3 (route over North Pole).

Step 2 — Initial direction: From 72°N heading to the North Pole = due North = 360°(T).

Step 3 — Track consistency: As the aircraft crosses the pole, "north" flips to "south" on the Mercator representation. The track direction changes from 360°T to 180°T — so No, it does not remain constant.

Instructor's Note: Verified against source key. No discrepancy.
Q7. You are at position A: 54°20'N 002°30'W. Given a ch.lat of 16°20'N and a ch.long of 20°30'W to B, what is the position of B?
Anchor: §8 — Ch.lat & Ch.long application
▶ Show answer & explanation
Position B: 70°40'N 023°00'W

Latitude: 54°20'N + 16°20'N = 70°40'N

Longitude: 002°30'W + 20°30'W = 023°00'W

Instructor's Note: Verified. No discrepancy.
Q8. You are at position C: 36°47'S 179°21'E. Given a ch.lat of 46°47'N and a ch.long of 20°30'E to D, what is the position of D?
Anchor: §8 — Ch.lat & Ch.long application
▶ Show answer & explanation
Position D: 10°00'N 160°09'W

Latitude: 36°47'S + 46°47'N (northward change crosses Equator): 46°47' − 36°47' = 10°00'N

Longitude: 179°21'E + 20°30'E = 199°51'E. Since > 180°: 360° − 199°51' = 160°09'W

Instructor's Note: Verified. No discrepancy. The longitude crosses the anti-meridian — a common exam trap.
Q9. What is the position of the Rhumb Line between 2 points relative to the Great Circle if the points are:
(a) In the Northern hemisphere   (b) In the Southern hemisphere
Anchor: §2 — Rhumb Line vs GC
▶ Show answer & explanation

(a) Northern hemisphere: Rhumb Line is nearer the Equator (South of the Great Circle)
(b) Southern hemisphere: Rhumb Line is nearer the Equator (North of the Great Circle)

In both hemispheres, the Rhumb Line lies nearer to the Equator, while the Great Circle bulges toward the nearer Pole. This is why the GC is the shorter path — it cuts across the "top" of the curved path rather than staying at the lower latitude.

Instructor's Note: Verified. No discrepancy.
Q10. Any Meridian Line is a:
Anchor: §3 — Lines that are both GC and Rhumb Lines
(a)   Rhumb Line
(b)   Semi Great Circle
(c)   Rhumb Line and a semi Great Circle ✓
▶ Show answer & explanation
Correct Answer: (c)

A meridian is simultaneously both:

  • A Rhumb Line — it cuts all other meridians at a constant angle of 0° (it runs exactly N–S, maintaining constant direction).
  • A semi-Great Circle — it forms one half of a Great Circle (the other half being its anti-meridian), whose plane passes through the Earth's centre.
Distractor Analysis:
(a) Correct but incomplete — a meridian is also a semi-Great Circle.
(b) Correct but incomplete — a meridian is also a Rhumb Line.
Instructor's Note: Source key: c. Verified. No discrepancy.
Q11. A Rhumb Line cuts all meridians at the same angle. This gives:
Anchor: §2 — Rhumb Line definition
(a)   The shortest distance between two points
(b)   A line which could never be a Great Circle track
(c)   A line of constant direction ✓
▶ Show answer & explanation
Correct Answer: (c) — A line of constant direction

Cutting all meridians at the same angle is equivalent to maintaining a constant compass direction. This is the defining property of a Rhumb Line and the basis of traditional compass navigation.

Distractor Analysis:
(a) Wrong — constant direction gives the longer (Rhumb Line) path, not the shortest (Great Circle).
(b) Wrong — meridians cut all other meridians at 0° (a constant angle) AND are semi-Great Circles. So a Rhumb Line CAN be a Great Circle track.
Instructor's Note: Source key: c. Verified. No discrepancy.

Master Reference Tables — Chapter 2

All Key Numerical Values

ParameterValueSection
1 NM (ICAO)1 852 m§5
1 NM (Standard/Admiralty)6 080 ft§5
1 NM (at Equator)~6 048 ft (shortest)§6
1 NM (International mean)6 076.1 ft§6
1 NM (at Poles)~6 108 ft (longest)§6
Earth circumference21 600 NM = 40 000 km§7
Equator to Pole5 400 NM = 10 000 km§7
1 km3 280 ft = 0.5400 NM§7
1 m3.28 ft§5
1 inch2.54 cm§5
1 statute mile5 280 ft§5
Antipodal distance10 800 NM = 20 000 km§8

GC Distance Cases — Quick Decision Tree

TestCaseMethod
Same longitude, both same hemiCase 1Ch.lat → NM
Same longitude, different hemiCase 2Sum lats → NM
Lons add to 180°, same hemiCase 3180° − sum of lats → NM
Lons add to 180°, diff hemiCase 4Draw diagram, route via nearer Pole
Both at Equator (lat = 0)Case 5Ch.long (shorter arc) → NM
Equal lats N & S, lons add to 180°Case 6Always 10 800 NM

DIID Rule — GC Track Direction Change

Hemisphere + DirectionGC Track Angle
North + East (→)Increasing
North + West (←)Decreasing
South + East (→)Decreasing
South + West (←)Increasing

GC always changes direction towards the Equator. Mnemonic: DIID read from North-West clockwise.

Answer Key Summary — No ⚑ Flags

QAnswer(s)
1a) 12°40'S   b) 109°55'S   c) 39°50'N   d) 21°55'
22 285 NM | 4 232 km
3a) 49°55'W   b) 05°40'W   c) 28°50'E   d) 56°42'W
4a) 01°29'N 002°05'W   b) 03°36'S 001°13'E   c) 00°26'N 005°22'E   d) 67°24'N 004°44'E   e) 00°01'N 014°36'E
5a) 90/167   b) 482/893   c) 3 360/6 223   d) 660/1 222   e) 10 800/20 000
6a) 360°(T)   b) No   c) Over N Pole, then track reverses to 180°T
770°40'N 023°00'W
810°00'N 160°09'W
9a) Nearer Equator (S of GC)   b) Nearer Equator (N of GC)
10c
11c

DGCA CPL/ATPL General Navigation Study Notes
Chapter 2 — Great Circles, Rhumb Lines & Directions on the Earth
Capt. Pankaj Pahil  |  www.ghostaviator.com
For personal study use only. Ghost Aviator Interactive Colour Edition.
Capt. Pankaj Pahil
www.ghostaviator.com